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md5加密算法C++程序

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发表于 2004-11-26 20:11:20 | 显示全部楼层 |阅读模式
#include "global.h"
+ m7 p, l3 {( A" E! ^3 I; i$ l* L #include "md5.h"
5 }1 m3 L! k* x' ^$ B* o
0 t% k) c6 U) k% a% ?4 T /* Constants for MD5Transform routine.
*/
( a" ]8 p* j& }
! a/ X3 T0 ?5 a7 [" ?# F8 z2 d) D
0 v: b1 u' t: P8 b3 h0 _( R#define S11 7
0 U/ G7 `% F% T) }#define S12 12
I" T* `( M/ L- ?8 V* j) p$ \$ A #define S13 17
& g4 R# w: z( M! b2 ^#define S14 22
/ C, F7 C0 C; L* z0 v# m #define S21 5
3 m4 o; X& w. Q) I* w& X1 Y* w$ G#define S22 9
) I& O8 ~0 _. U M. F0 X- l; T- O0 g #define S23 14
* p1 f5 P6 o5 S! ] #define S24 20
, a/ {7 I& g7 i5 e* l#define S31 4
# `, u( |. n7 |: `, ]. [3 i #define S32 11
' R: q6 s4 c7 M0 x( f, V#define S33 16
- Q4 {* p, y/ e8 k8 J #define S34 23
% b) |& T2 u4 k% [1 F/ Y) T; Q#define S41 6
) {: D+ }" O* V! [#define S42 10
! j( E9 x; P9 Z( ~% R% c6 a% e#define S43 15
3 k/ c! E% ^( F #define S44 21
; s4 Q6 N- f0 M& }( z5 Y, O
$ U ^% R% A( q! U- I' [0 m- Jstatic void MD5Transform PROTO_LIST ((UINT4 [4], unsigned char [64]));
: @* `! ^8 L) i' `& u1 j static void Encode PROTO_LIST
((unsigned char *, UINT4 *, unsigned int));
% _2 m- }6 u1 D static void Decode PROTO_LIST
((UINT4 *, unsigned char *, unsigned int));
/ o/ O/ R q$ {: L! f8 X) sstatic void MD5_memcpy PROTO_LIST ((POINTER, POINTER, unsigned int));
, a" M% D, v! T( U( ~; pstatic void MD5_memset PROTO_LIST ((POINTER, int, unsigned int));
- ^/ e4 G7 k( G
. o, K6 j% U* }: u4 j" W# d2 s! bstatic unsigned char PADDING[64] = {
0x80, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
; Z( w O8 f* f3 ]};
9 {4 A# t8 Y& w. c. _2 I/ p
5 _$ M% z9 k8 n* D/* F, G, H and I are basic MD5 functions.
*/
, w/ b6 d2 C& N7 S4 \' H; ?! v#define F(x, y, z) (((x) & (y)) | ((~x) & (z)))
2 {& v. Y: y8 W1 ^ #define G(x, y, z) (((x) & (z)) | ((y) & (~z)))
+ a1 G+ [* B) G#define H(x, y, z) ((x) ^ (y) ^ (z))
0 E- f: f8 g) [) K4 X( P- T6 r#define I(x, y, z) ((y) ^ ((x) | (~z)))
2 ~. k2 T5 w% U/ {: S
2 T+ S; O0 s" c& [4 j/ I /* ROTATE_LEFT rotates x left n bits.
*/
; O7 P' V6 D1 e/ ]" D1 a #define ROTATE_LEFT(x, n) (((x) << (n)) | ((x) >> (32-(n))))
; W# D- x& `+ r0 I
7 B8 p+ Y3 n5 V9 M W! \2 C /* FF, GG, HH, and II transformations for rounds 1, 2, 3, and 4.
; f3 D, x/ i1 W! b6 URotation is separate from addition to prevent recomputation.
*/
/ k, |9 v( u7 e6 v. p#define FF(a, b, c, d, x, s, ac) { \
(a) += F ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
3 f- N0 O3 y' d2 f/ A; s #define GG(a, b, c, d, x, s, ac) { \
(a) += G ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
l2 C3 R B% M8 B, _! ^#define HH(a, b, c, d, x, s, ac) { \
(a) += H ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
0 z2 l' I8 V6 B* l3 v+ K #define II(a, b, c, d, x, s, ac) { \
(a) += I ((b), (c), (d)) + (x) + (UINT4)(ac); \
(a) = ROTATE_LEFT ((a), (s)); \
(a) += (b); \
}
5 R- u* I, c' X8 \
( Z" M0 p# U! ]3 r& |0 W4 i' K* v /* MD5 initialization. Begins an MD5 operation, writing a new context.
*/
U4 e& h8 A5 ~ R void MD5Init (context)
' s' } t6 D1 @3 [) r9 y2 q* N MD5_CTX *context; /* context */
9 ] n" U) C# ]{
context->count[0] = context->count[1] = 0;
/* Load magic initialization constants.
0 n. E9 Y& A& e) Y */
context->state[0] = 0x67452301;
context->state[1] = 0xefcdab89;
context->state[2] = 0x98badcfe;
context->state[3] = 0x10325476;
1 @8 G0 m% a6 e o; ?, H }
6 C6 N6 G; ^5 u
# f0 O; e' c. q8 P /* MD5 block update operation. Continues an MD5 message-digest
operation, processing another message block, and updating the
context.
*/
5 Q$ X2 L% T$ N; b# C- g) D( t4 f; Vvoid MD5Update (context, input, inputLen)
" o a" a$ Y# ] MD5_CTX *context; /* context */
% ^' c, V y+ o4 ] X0 f" Z2 Iunsigned char *input; /* input block */
* `( {& B" H. A( i p; f9 D unsigned int inputLen; /* length of input block */
, `1 V% x& ^: b) m( h& L+ L' \ {
unsigned int i, index, partLen;
9 G% B9 ?0 _* k; k
/* Compute number of bytes mod 64 */
index = (unsigned int)((context->count[0] >> 3) & 0x3F);
$ b/ S' F% M& t
/* Update number of bits */
if ((context->count[0] += ((UINT4)inputLen << 3))
&
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Rank: 7Rank: 7Rank: 7

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发表于 2004-11-26 20:22:48 | 显示全部楼层

md5加密算法C++程序


# P: J3 n# T, y' g* w1 f0 g
p5 a) s o7 ^* P8 J
guoyun786@sohu.com
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